What is longdivision (3x^2+1)/(2x^2-5) ?

The solution to longdivision (3x^2+1)/(2x^2-5) is 3/2+(17)/(2(2x^2-5))

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longdivision (3x^2+1)/(2x^2-5)

long division

\frac{3 x ^{2} + 1}{2 x ^{2} - 5}

\frac{3}{2} + \frac{17}{2 ( 2 x ^{2} - 5 )}

Solution steps

\frac{3 x ^{2} + 1}{2 x ^{2} - 5}

Divide

\frac{3 x ^{2} + 1}{2 x ^{2} - 5} : \frac{3 x ^{2} + 1}{2 x ^{2} - 5} = \frac{3}{2} + \frac{\frac{17}{2}}{2 x ^{2} - 5}

= \frac{3}{2} + \frac{\frac{17}{2}}{2 x ^{2} - 5}

Simplify

= \frac{3}{2} + \frac{17}{2 ( 2 x ^{2} - 5 )}

f (x) = x^{3} x

x \to - 3 + lim (x^{3} + 27)

\int_{0}^{8} e^{x} sin (x) d x

\frac{\partial}{\partial u} (u^{2} + v)

x \to 0 + lim (x^{x^{5}})

What is longdivision (3x^2+1)/(2x^2-5) ?
The solution to longdivision (3x^2+1)/(2x^2-5) is 3/2+(17)/(2(2x^2-5))