What is the derivative of ax+b/x ?

The derivative of ax+b/x is a-b/(x^2)

What is the first derivative of ax+b/x ?

The first derivative of ax+b/x is a-b/(x^2)

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\frac{d}{d x} (a x + \frac{b}{x})

a - \frac{b}{x ^{2}}

Solution steps

\frac{d}{d x} (a x + \frac{b}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x) + \frac{d}{d x} (\frac{b}{x})

\frac{d}{d x} (a x) = a

\frac{d}{d x} (\frac{b}{x}) = - \frac{b}{x ^{2}}

= a - \frac{b}{x ^{2}}

\frac{d}{d x} (\frac{e ^{x}}{x ^{2} - 1})

e^{- 7 t}

\int x \cdot sin (x) cos (x) d x

n = 7 \sum \infty \frac{1}{n ln ( n )}

\int_{0}^{3} x^{2} - 9 d x

What is the derivative of ax+b/x ?
The derivative of ax+b/x is a-b/(x^2)
What is the first derivative of ax+b/x ?
The first derivative of ax+b/x is a-b/(x^2)