What is the integral of 2x^3sin(x^4) ?

The integral of 2x^3sin(x^4) is -1/2 cos(x^4)+C

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integral of 2x^3sin(x^4)

\int 2 x^{3} sin (x^{4}) d x

- \frac{1}{2} cos (x^{4}) + C

Solution steps

\int 2 x^{3} sin (x^{4}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x^{3} sin (x^{4}) d x

Apply u-substitution

: \int \frac{sin ( u )}{4} d u

= 2 \cdot \int \frac{sin ( u )}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{4} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 2 \cdot \frac{1}{4} (- cos (u))

Substitute back

u = x^{4}

= 2 \cdot \frac{1}{4} (- cos (x^{4}))

Simplify

2 \cdot \frac{1}{4} (- cos (x^{4})) : - \frac{1}{2} cos (x^{4})

= - \frac{1}{2} cos (x^{4})

Add a constant to the solution

= - \frac{1}{2} cos (x^{4}) + C

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What is the integral of 2x^3sin(x^4) ?
The integral of 2x^3sin(x^4) is -1/2 cos(x^4)+C