What is (\partial)/(\partial x)(sqrt(2-x^2-y^2)) ?

The answer to (\partial)/(\partial x)(sqrt(2-x^2-y^2)) is -x/(sqrt(2-x^2-y^2))

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(\partial)/(\partial x)(sqrt(2-x^2-y^2))

\frac{\partial}{\partial x} (2 - x^{2} - y^{2})

- \frac{x}{2 - x ^{2} - y ^{2}}

Solution steps

\frac{\partial}{\partial x} (2 - x^{2} - y^{2})

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 2 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (2 - x^{2} - y^{2})

= \frac{1}{2 2 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (2 - x^{2} - y^{2})

\frac{\partial}{\partial x} (2 - x^{2} - y^{2}) = - 2 x

= \frac{1}{2 2 - x ^{2} - y ^{2}} (- 2 x)

Simplify

\frac{1}{2 2 - x ^{2} - y ^{2}} (- 2 x) : - \frac{x}{2 - x ^{2} - y ^{2}}

= - \frac{x}{2 - x ^{2} - y ^{2}}

\frac{d}{d x} (- e^{- 4 x})

\int_{3}^{\infty} \frac{e ^{- \frac{1}{x}}}{x ^{2}} d x

(cos (x))^{^{'}}

\frac{\partial}{\partial x} (\frac{y}{1 + x})

\int (x + 1) d x

What is (\partial)/(\partial x)(sqrt(2-x^2-y^2)) ?
The answer to (\partial)/(\partial x)(sqrt(2-x^2-y^2)) is -x/(sqrt(2-x^2-y^2))