What is the integral of (6+sin(x))/(cos(x)) ?

The integral of (6+sin(x))/(cos(x)) is 6ln|tan(x)+sec(x)|-ln|cos(x)|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (6+sin(x))/(cos(x))

\int \frac{6 + sin ( x )}{cos ( x )} d x

6 ln ∣ tan (x) + sec (x) ∣ - ln ∣ cos (x) ∣ + C

Solution steps

\int \frac{6 + sin ( x )}{cos ( x )} d x

Expand

\frac{6 + sin ( x )}{cos ( x )} : \frac{6}{cos ( x )} + \frac{sin ( x )}{cos ( x )}

= \int \frac{6}{cos ( x )} + \frac{sin ( x )}{cos ( x )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6}{cos ( x )} d x + \int \frac{sin ( x )}{cos ( x )} d x

\int \frac{6}{cos ( x )} d x = 6 ln ∣ tan (x) + sec (x) ∣

\int \frac{sin ( x )}{cos ( x )} d x = - ln ∣ cos (x) ∣

= 6 ln ∣ tan (x) + sec (x) ∣ - ln ∣ cos (x) ∣

Add a constant to the solution

= 6 ln ∣ tan (x) + sec (x) ∣ - ln ∣ cos (x) ∣ + C

\int \frac{( x - 1 ) ^{2}}{x x} d x

\int e^{2 x} \cdot cos (6 x) d x

\int (x^{2} - 2) cos (2 x) d x

\int (sin (x) sin (3 x)) d x

\int \frac{x ^{3} + 2 x ^{2} + 3 x + 7}{x ^{2} - x - 6} d x

What is the integral of (6+sin(x))/(cos(x)) ?
The integral of (6+sin(x))/(cos(x)) is 6ln|tan(x)+sec(x)|-ln|cos(x)|+C