What is the integral of (3x^2+6x-2) ?

The integral of (3x^2+6x-2) is x^3+3x^2-2x+C

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integral of (3x^2+6x-2)

\int (3 x^{2} + 6 x - 2) d x

x^{3} + 3 x^{2} - 2 x + C

Solution steps

\int 3 x^{2} + 6 x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x + \int 6 x d x - \int 2 d x

\int 3 x^{2} d x = x^{3}

\int 6 x d x = 3 x^{2}

\int 2 d x = 2 x

= x^{3} + 3 x^{2} - 2 x

Add a constant to the solution

= x^{3} + 3 x^{2} - 2 x + C

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What is the integral of (3x^2+6x-2) ?
The integral of (3x^2+6x-2) is x^3+3x^2-2x+C