What is the integral of (tan^2(x))/(sin^2(x)) ?

The integral of (tan^2(x))/(sin^2(x)) is tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (tan^2(x))/(sin^2(x))

\int \frac{tan ^{2} ( x )}{sin ^{2} ( x )} d x

tan (x) + C

Solution steps

\int \frac{tan ^{2} ( x )}{sin ^{2} ( x )} d x

Simplify

\frac{tan ^{2} ( x )}{sin ^{2} ( x )} : sec^{2} (x)

= \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= tan (x)

Add a constant to the solution

= tan (x) + C

\int 12 cos (4 x) sin^{4} (4 x) d x

\int x^{1} - 1 d x

\int sinh^{3} (x) cosh (x) d x

\int 20 x^{3} (5 x^{4} - 1)^{3} d x

\int \frac{x}{( x - 2 ) ( x - 1 ) ^{2}} d x

What is the integral of (tan^2(x))/(sin^2(x)) ?
The integral of (tan^2(x))/(sin^2(x)) is tan(x)+C