What is the integral of (x-a/x)^2 ?

The integral of (x-a/x)^2 is (x^3)/3-2ax-(a^2)/x+C

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integral of (x-a/x)^2

\int (x - \frac{a}{x})^{2} d x

\frac{x ^{3}}{3} - 2 a x - \frac{a ^{2}}{x} + C

Solution steps

\int (x - \frac{a}{x})^{2} d x

Simplify

(x - \frac{a}{x})^{2} : x^{2} - 2 a + \frac{a ^{2}}{x ^{2}}

= \int x^{2} - 2 a + \frac{a ^{2}}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 2 a d x + \int \frac{a ^{2}}{x ^{2}} d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 2 a d x = 2 a x

\int \frac{a ^{2}}{x ^{2}} d x = - \frac{a ^{2}}{x}

= \frac{x ^{3}}{3} - 2 a x - \frac{a ^{2}}{x}

Add a constant to the solution

= \frac{x ^{3}}{3} - 2 a x - \frac{a ^{2}}{x} + C

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What is the integral of (x-a/x)^2 ?
The integral of (x-a/x)^2 is (x^3)/3-2ax-(a^2)/x+C