What is the integral of (sin(4x))/(tan(4x)) ?

The integral of (sin(4x))/(tan(4x)) is 1/4 sin(4x)+C

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integral of (sin(4x))/(tan(4x))

\int \frac{sin ( 4 x )}{tan ( 4 x )} d x

\frac{1}{4} sin (4 x) + C

Solution steps

\int \frac{sin ( 4 x )}{tan ( 4 x )} d x

Rewrite using trig identities

= \int cos (4 x) d x

Apply u-substitution

: \int cos (u) \frac{1}{4} d u

= \int cos (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{4} sin (u)

Substitute back

u = 4 x

= \frac{1}{4} sin (4 x)

Add a constant to the solution

= \frac{1}{4} sin (4 x) + C

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What is the integral of (sin(4x))/(tan(4x)) ?
The integral of (sin(4x))/(tan(4x)) is 1/4 sin(4x)+C