What is the integral of (e^4-2^e) ?

The integral of (e^4-2^e) is (e^4-2^e)x+C

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integral of (e^4-2^e)

\int (e^{4} - 2^{e}) d x

(e^{4} - 2^{e}) x + C

Solution steps

\int e^{4} - 2^{e} d x

Integral of a constant:

\int a d x = a x

= (e^{4} - 2^{e}) x

Add a constant to the solution

= (e^{4} - 2^{e}) x + C

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