What is the integral of 4/(x^{-3)} ?

The integral of 4/(x^{-3)} is x^4+C

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integral of 4/(x^{-3)}

\int \frac{4}{x ^{- 3}} d x

x^{4} + C

Solution steps

\int \frac{4}{x ^{- 3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{x ^{- 3}} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= 4 \cdot \frac{x ^{4}}{4}

Simplify

4 \cdot \frac{x ^{4}}{4} : x^{4}

= x^{4}

Add a constant to the solution

= x^{4} + C

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