What is area f(x)=x*sqrt(1-x^2),[0,1] ?

The answer to area f(x)=x*sqrt(1-x^2),[0,1] is 1/3

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area f(x)=x*sqrt(1-x^2),[0,1]

area

f (x) = x \cdot 1 - x^{2}, [0, 1]

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} ∣ x ∣ 1 - x^{2} d x

Solve

\int_{0}^{1} ∣ x ∣ 1 - x^{2} d x : \frac{1}{3}

The area is:

= \frac{1}{3}

\frac{1}{p ( p + 1 )}

x \to - 3 lim (x^{2} + 27)

\int x^{2} (x - \frac{2}{x}) d x

f (x) = arctan (\frac{1 + x}{1 - x})

\frac{d y}{d x} = 15 sin (\frac{π}{20} (x - 2)) + 2

What is area f(x)=x*sqrt(1-x^2),[0,1] ?
The answer to area f(x)=x*sqrt(1-x^2),[0,1] is 1/3