What is the integral of (3x+4)e^x ?

The integral of (3x+4)e^x is 3e^xx+e^x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3x+4)e^x

\int (3 x + 4) e^{x} d x

3 e^{x} x + e^{x} + C

Solution steps

\int (3 x + 4) e^{x} d x

Apply Integration By Parts

: (3 x + 4) e^{x} - \int 3 e^{x} d x

= (3 x + 4) e^{x} - \int 3 e^{x} d x

\int 3 e^{x} d x = 3 e^{x}

= (3 x + 4) e^{x} - 3 e^{x}

Simplify

(3 x + 4) e^{x} - 3 e^{x} : 3 e^{x} x + e^{x}

= 3 e^{x} x + e^{x}

Add a constant to the solution

= 3 e^{x} x + e^{x} + C

\int cot^{4} (y) d y

\int x^{\frac{1}{8}} ln (x) d x

\int x^{2} + 2 x - 7 d x

\int \frac{4}{x 4 - x ^{2}} d x

\int - \frac{2}{7} x cos (\frac{2}{3} x) d x