What is the integral from 0 to 2 of sin(x^2) ?

The integral from 0 to 2 of sin(x^2) is sqrt(pi/2)\S(sqrt(2/pi)*2)-sqrt(pi/2)\S(sqrt(2/pi)*0)

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integral from 0 to 2 of sin(x^2)

\int_{0}^{2} sin (x^{2}) d x

\frac{π}{2} § (\frac{2}{π} \cdot 2) - \frac{π}{2} § (\frac{2}{π} \cdot 0)

Solution steps

\int_{0}^{2} sin (x^{2}) d x

Use the nonelementary integral:

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x)

= [\frac{π}{2} § (\frac{2}{π} x)]_{0}^{2}

Compute the boundaries:

\frac{π}{2} § (\frac{2}{π} \cdot 2) - \frac{π}{2} § (\frac{2}{π} \cdot 0)

= \frac{π}{2} § (\frac{2}{π} \cdot 2) - \frac{π}{2} § (\frac{2}{π} \cdot 0)

\frac{\partial}{\partial x} (- x y z^{2} + 16)

y = x - x^{3} (1)

\frac{5}{s ^{2} + 4}

\frac{\partial}{\partial x} (- 4 x^{5} y^{- 5})

\frac{\partial}{\partial y} (1 + x y^{2})

What is the integral from 0 to 2 of sin(x^2) ?
The integral from 0 to 2 of sin(x^2) is sqrt(pi/2)\S(sqrt(2/pi)*2)-sqrt(pi/2)\S(sqrt(2/pi)*0)