What is the integral of csc^3(x)cos^3(x) ?

The integral of csc^3(x)cos^3(x) is -1/2 csc^2(x)-ln|sin(x)|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of csc^3(x)cos^3(x)

\int csc^{3} (x) cos^{3} (x) d x

- \frac{1}{2} csc^{2} (x) - ln ∣ sin (x) ∣ + C

Solution steps

\int csc^{3} (x) cos^{3} (x) d x

Rewrite using trig identities

= \int \frac{( 1 - sin ^{2} ( x ) ) cos ( x )}{sin ^{3} ( x )} d x

Apply u-substitution

: \int \frac{1 - u ^{2}}{u ^{3}} d u

= \int \frac{1 - u ^{2}}{u ^{3}} d u

Expand

\frac{1 - u ^{2}}{u ^{3}} : \frac{1}{u ^{3}} - \frac{1}{u}

= \int \frac{1}{u ^{3}} - \frac{1}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{u ^{3}} d u - \int \frac{1}{u} d u

\int \frac{1}{u ^{3}} d u = - \frac{1}{2 u ^{2}}

\int \frac{1}{u} d u = ln ∣ u ∣

= - \frac{1}{2 u ^{2}} - ln ∣ u ∣

Substitute back

u = sin (x)

= - \frac{1}{2 sin ^{2} ( x )} - ln ∣ sin (x) ∣

Simplify

- \frac{1}{2 sin ^{2} ( x )} - ln ∣ sin (x) ∣ : - \frac{1}{2} csc^{2} (x) - ln ∣ sin (x) ∣

= - \frac{1}{2} csc^{2} (x) - ln ∣ sin (x) ∣

Add a constant to the solution

= - \frac{1}{2} csc^{2} (x) - ln ∣ sin (x) ∣ + C

\int 12 + 8 x - 3 x^{2} d x

\int (3 t^{2} - 5 t + 2) d t

\int \frac{1}{6 + e ^{- 8 x}} d x

\int (sin (2 x) + cos (x))^{2} d x

\int \frac{5}{x ^{2} + 4} d x

What is the integral of csc^3(x)cos^3(x) ?
The integral of csc^3(x)cos^3(x) is -1/2 csc^2(x)-ln|sin(x)|+C