What is the integral of (e^x(x^2+1))/((x+1)^2) ?

The integral of (e^x(x^2+1))/((x+1)^2) is -(e^x(x^2+1))/(x+1)+e^xx+C

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integral of (e^x(x^2+1))/((x+1)^2)

\int \frac{e ^{x} ( x ^{2} + 1 )}{( x + 1 ) ^{2}} d x

- \frac{e ^{x} ( x ^{2} + 1 )}{x + 1} + e^{x} x + C

Solution steps

\int \frac{e ^{x} ( x ^{2} + 1 )}{( x + 1 ) ^{2}} d x

Apply Integration By Parts

: - \frac{e ^{x} ( x ^{2} + 1 )}{x + 1} - \int - e^{x} (x + 1) d x

= - \frac{e ^{x} ( x ^{2} + 1 )}{x + 1} - \int - e^{x} (x + 1) d x

\int - e^{x} (x + 1) d x = - e^{x} x

= - \frac{e ^{x} ( x ^{2} + 1 )}{x + 1} - (- e^{x} x)

Simplify

= - \frac{e ^{x} ( x ^{2} + 1 )}{x + 1} + e^{x} x

Add a constant to the solution

= - \frac{e ^{x} ( x ^{2} + 1 )}{x + 1} + e^{x} x + C

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What is the integral of (e^x(x^2+1))/((x+1)^2) ?
The integral of (e^x(x^2+1))/((x+1)^2) is -(e^x(x^2+1))/(x+1)+e^xx+C