What is the integral of 0.1682x^2+0.0987x+0.4774 ?

The integral of 0.1682x^2+0.0987x+0.4774 is 0.05606…x^3+0.04935x^2+0.4774x+C

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integral of 0.1682x^2+0.0987x+0.4774

\int 0.1682 x^{2} + 0.0987 x + 0.4774 d x

0.05606 \dots x^{3} + 0.04935 x^{2} + 0.4774 x + C

Solution steps

\int 0.1682 x^{2} + 0.0987 x + 0.4774 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.1682 x^{2} d x + \int 0.0987 x d x + \int 0.4774 d x

\int 0.1682 x^{2} d x = 0.05606 \dots x^{3}

\int 0.0987 x d x = 0.04935 x^{2}

\int 0.4774 d x = 0.4774 x

= 0.05606 \dots x^{3} + 0.04935 x^{2} + 0.4774 x

Add a constant to the solution

= 0.05606 \dots x^{3} + 0.04935 x^{2} + 0.4774 x + C

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What is the integral of 0.1682x^2+0.0987x+0.4774 ?
The integral of 0.1682x^2+0.0987x+0.4774 is 0.05606…x^3+0.04935x^2+0.4774x+C