What is the integral of e^{2x}(1-e^{2x})^{3/2} ?

The integral of e^{2x}(1-e^{2x})^{3/2} is -1/5 (1-e^{2x})^{5/2}+C

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integral of e^{2x}(1-e^{2x})^{3/2}

\int e^{2 x} (1 - e^{2 x})^{\frac{3}{2}} d x

- \frac{1}{5} (1 - e^{2 x})^{\frac{5}{2}} + C

Solution steps

\int e^{2 x} (1 - e^{2 x})^{\frac{3}{2}} d x

Apply u-substitution

: \int - \frac{u ^{\frac{3}{2}}}{2} d u

= \int - \frac{u ^{\frac{3}{2}}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int u^{\frac{3}{2}} d u

Apply the Power Rule

: \frac{2}{5} u^{\frac{5}{2}}

= - \frac{1}{2} \cdot \frac{2}{5} u^{\frac{5}{2}}

Substitute back

u = 1 - e^{2 x}

= - \frac{1}{2} \cdot \frac{2}{5} (1 - e^{2 x})^{\frac{5}{2}}

Simplify

- \frac{1}{2} \cdot \frac{2}{5} (1 - e^{2 x})^{\frac{5}{2}} : - \frac{1}{5} (1 - e^{2 x})^{\frac{5}{2}}

= - \frac{1}{5} (1 - e^{2 x})^{\frac{5}{2}}

Add a constant to the solution

= - \frac{1}{5} (1 - e^{2 x})^{\frac{5}{2}} + C

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What is the integral of e^{2x}(1-e^{2x})^{3/2} ?
The integral of e^{2x}(1-e^{2x})^{3/2} is -1/5 (1-e^{2x})^{5/2}+C