What is the integral of 7^xx ?

The integral of 7^xx is (7^xx)/(ln(7))-(7^x)/(ln^2(7))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 7^xx

\int 7^{x} x d x

\frac{7 ^{x} x}{ln ( 7 )} - \frac{7 ^{x}}{ln ^{2} ( 7 )} + C

Solution steps

\int 7^{x} x d x

Apply Integration By Parts

: \frac{7 ^{x} x}{ln ( 7 )} - \int \frac{7 ^{x}}{ln ( 7 )} d x

= \frac{7 ^{x} x}{ln ( 7 )} - \int \frac{7 ^{x}}{ln ( 7 )} d x

\int \frac{7 ^{x}}{ln ( 7 )} d x = \frac{7 ^{x}}{ln ^{2} ( 7 )}

= \frac{7 ^{x} x}{ln ( 7 )} - \frac{7 ^{x}}{ln ^{2} ( 7 )}

Add a constant to the solution

= \frac{7 ^{x} x}{ln ( 7 )} - \frac{7 ^{x}}{ln ^{2} ( 7 )} + C

\int \frac{1}{x ^{2}} \frac{1 - x}{1 + x} d x

\int \frac{2 x}{x - 5} d x

\int (x^{2} + 4 x)^{5} (x + 2) d x

\int \frac{x + 1}{( x - 3 ) ^{3}} d x

\int \frac{x ^{2}}{x ^{2} + 19} d x

What is the integral of 7^xx ?
The integral of 7^xx is (7^xx)/(ln(7))-(7^x)/(ln^2(7))+C