What is the integral of (tan(x))/(sin^2(x)) ?

The integral of (tan(x))/(sin^2(x)) is ln|tan(x)|+C

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integral of (tan(x))/(sin^2(x))

\int \frac{tan ( x )}{sin ^{2} ( x )} d x

ln ∣ tan (x) ∣ + C

Solution steps

\int \frac{tan ( x )}{sin ^{2} ( x )} d x

Rewrite using trig identities

= \int \frac{sec ( x )}{sin ( x )} d x

Apply Trigonometric Substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = tan (x)

= ln ∣ tan (x) ∣

Add a constant to the solution

= ln ∣ tan (x) ∣ + C

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What is the integral of (tan(x))/(sin^2(x)) ?
The integral of (tan(x))/(sin^2(x)) is ln|tan(x)|+C