What is (\partial)/(\partial x)(3x(4+y)^{-1}) ?

The answer to (\partial)/(\partial x)(3x(4+y)^{-1}) is 3/(4+y)

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(\partial)/(\partial x)(3x(4+y)^{-1})

\frac{\partial}{\partial x} (3 x (4 + y)^{- 1})

\frac{3}{4 + y}

Solution steps

\frac{\partial}{\partial x} (3 x (4 + y)^{- 1})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 (4 + y)^{- 1} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 3 (4 + y)^{- 1} \cdot 1

Simplify

3 (4 + y)^{- 1} \cdot 1 : \frac{3}{4 + y}

= \frac{3}{4 + y}

\int_{0}^{6} \frac{1}{36 + x ^{2}} d x

\frac{\partial}{\partial x} (e^{3 y})

\int \frac{z}{z ^{4} + 4} d z

y^{^{''}} + 4 y^{^{'}} + 3 = 0

\frac{d y}{d x} = (x + y - 3)^{2}

What is (\partial)/(\partial x)(3x(4+y)^{-1}) ?
The answer to (\partial)/(\partial x)(3x(4+y)^{-1}) is 3/(4+y)