What is the integral of sech^2(3x) ?

The integral of sech^2(3x) is 1/3 tanh(3x)+C

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integral of sech^2(3x)

\int sech^{2} (3 x) d x

\frac{1}{3} tanh (3 x) + C

Solution steps

\int sech^{2} (3 x) d x

Apply u-substitution

: \int sech^{2} (u) \frac{1}{3} d u

= \int sech^{2} (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int sech^{2} (u) d u

Use the common integral:

\int sech^{2} (u) d u = tanh (u)

= \frac{1}{3} tanh (u)

Substitute back

u = 3 x

= \frac{1}{3} tanh (3 x)

Add a constant to the solution

= \frac{1}{3} tanh (3 x) + C

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What is the integral of sech^2(3x) ?
The integral of sech^2(3x) is 1/3 tanh(3x)+C