What is the integral of (3x-1)/(x^2-2x-3) ?

The integral of (3x-1)/(x^2-2x-3) is ln|x+1|+2ln|x-3|+C

Popular >

integral of (3x-1)/(x^2-2x-3)

\int \frac{3 x - 1}{x ^{2} - 2 x - 3} d x

ln ∣ x + 1 ∣ + 2 ln ∣ x - 3 ∣ + C

Solution steps

\int \frac{3 x - 1}{x ^{2} - 2 x - 3} d x

Take the partial fraction of

\frac{3 x - 1}{x ^{2} - 2 x - 3} : \frac{1}{x + 1} + \frac{2}{x - 3}

= \int \frac{1}{x + 1} + \frac{2}{x - 3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x + 1} d x + \int \frac{2}{x - 3} d x

\int \frac{1}{x + 1} d x = ln ∣ x + 1 ∣

\int \frac{2}{x - 3} d x = 2 ln ∣ x - 3 ∣

= ln ∣ x + 1 ∣ + 2 ln ∣ x - 3 ∣

Add a constant to the solution

= ln ∣ x + 1 ∣ + 2 ln ∣ x - 3 ∣ + C

\int \frac{1}{3 + 9 - x ^{2}} d x

\int 8 sin (- 4 x) cos^{3} (- 4 x) d x

\int x^{2} (ln (x))^{3} d x

\int \frac{1}{sin ( t ) - cos ( t )} d t

\int \frac{x ( 5 - x ^{2} )}{( x ^{2} + 1 )} d x

What is the integral of (3x-1)/(x^2-2x-3) ?
The integral of (3x-1)/(x^2-2x-3) is ln|x+1|+2ln|x-3|+C