What is the integral of x^8sqrt(x) ?

The integral of x^8sqrt(x) is 2/19 x^{19/2}+C

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integral of x^8sqrt(x)

\int x^{8} x d x

\frac{2}{19} x^{\frac{19}{2}} + C

Solution steps

\int x^{8} x d x

Simplify

x^{8} x : x^{\frac{17}{2}}

= \int x^{\frac{17}{2}} d x

Apply the Power Rule

: \frac{2}{19} x^{\frac{19}{2}}

= \frac{2}{19} x^{\frac{19}{2}}

Add a constant to the solution

= \frac{2}{19} x^{\frac{19}{2}} + C

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What is the integral of x^8sqrt(x) ?
The integral of x^8sqrt(x) is 2/19 x^{19/2}+C