What is (\partial)/(\partial y)(2xe^{-y}) ?

The answer to (\partial)/(\partial y)(2xe^{-y}) is -2e^{-y}x

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(\partial)/(\partial y)(2xe^{-y})

\frac{\partial}{\partial y} (2 x e^{- y})

- 2 e^{- y} x

Solution steps

\frac{\partial}{\partial y} (2 x e^{- y})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x \frac{\partial}{\partial y} (e^{- y})

Apply the chain rule:

e^{- y} \frac{\partial}{\partial y} (- y)

= e^{- y} \frac{\partial}{\partial y} (- y)

\frac{\partial}{\partial y} (- y) = - 1

= 2 x e^{- y} (- 1)

Simplify

= - 2 e^{- y} x

x \frac{d y}{d x} - y = 2 x^{2}

\frac{\partial}{\partial x} (3^{x})

\frac{\partial}{\partial x} (7 x y^{3} + 5)

t^{2} y^{^{'}} + 2 t y - y^{3} = 0

\frac{1}{( s ^{2} + 1 ) ( s ^{2} + 3 )}

What is (\partial)/(\partial y)(2xe^{-y}) ?
The answer to (\partial)/(\partial y)(2xe^{-y}) is -2e^{-y}x