What is the integral of (x^2+3x)(2x+3) ?

The integral of (x^2+3x)(2x+3) is ((x^2+3x)^2)/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^2+3x)(2x+3)

\int (x^{2} + 3 x) (2 x + 3) d x

\frac{( x ^{2} + 3 x ) ^{2}}{2} + C

Solution steps

\int (x^{2} + 3 x) (2 x + 3) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = x^{2} + 3 x

= \frac{( x ^{2} + 3 x ) ^{2}}{2}

Add a constant to the solution

= \frac{( x ^{2} + 3 x ) ^{2}}{2} + C

\int \frac{4 sin ( x )}{cos ( x )} d x

\int (2 x - 2) e^{3 x} d x

\int \frac{8 x ^{2} + 2}{2 x ^{3} + x} d x

\int \frac{7}{5 x 25 x ^{2} - 7} d x

What is the integral of (x^2+3x)(2x+3) ?
The integral of (x^2+3x)(2x+3) is ((x^2+3x)^2)/2+C