What is the integral of (cos^2(4x)+sin^2(4x)) ?

The integral of (cos^2(4x)+sin^2(4x)) is x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (cos^2(4x)+sin^2(4x))

\int (cos^{2} (4 x) + sin^{2} (4 x)) d x

x + C

Solution steps

\int cos^{2} (4 x) + sin^{2} (4 x) d x

Rewrite using trig identities

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C

\int 3 x \cdot sin (2 x) d x

\int cos (3 x) cos (6 x) d x

\int \frac{x ^{3} - 2 x ^{2} + 3 x + 2}{x ( x ^{2} + 1 ) ^{2}} d x

\int (\frac{e ^{4 x} - 1}{e ^{3 x}}) d x

\int \frac{5}{2} x^{\frac{3}{2}} d x

What is the integral of (cos^2(4x)+sin^2(4x)) ?
The integral of (cos^2(4x)+sin^2(4x)) is x+C