What is the derivative of y=5e^x+4/(\sqrt[3]{x)} ?

The derivative of y=5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}

What is the first derivative of y=5e^x+4/(\sqrt[3]{x)} ?

The first derivative of y=5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}

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derivative of

5 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

= 5 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

1 - x, 0

y^{^{'''}} + 3 y^{^{''}} - 4 y = 0

y^{^{''}} + 3 y^{^{'}} + 2 y = cos (2 x)

y^{^{'}} + y - e^{x} = 0

y = x, y = x^{3}, [- 1, 2]

What is the derivative of y=5e^x+4/(\sqrt[3]{x)} ?
The derivative of y=5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}
What is the first derivative of y=5e^x+4/(\sqrt[3]{x)} ?
The first derivative of y=5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}