What is the integral of (6x^2+2x+3) ?

The integral of (6x^2+2x+3) is 2x^3+x^2+3x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (6x^2+2x+3)

\int (6 x^{2} + 2 x + 3) d x

2 x^{3} + x^{2} + 3 x + C

Solution steps

\int 6 x^{2} + 2 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{2} d x + \int 2 x d x + \int 3 d x

\int 6 x^{2} d x = 2 x^{3}

\int 2 x d x = x^{2}

\int 3 d x = 3 x

= 2 x^{3} + x^{2} + 3 x

Add a constant to the solution

= 2 x^{3} + x^{2} + 3 x + C

\int x^{6} cos (x^{7}) d x

\int + sin^{5} (\frac{x}{3}) cos (\frac{x}{3}) d x

\int \frac{( 4 - 2 x + 1 )}{1 - 2 x} d x

\int (4 x^{5} - 3 x^{4} - 25) d x

\int (sin (x) - cos (y) + \frac{y}{x}) d y

What is the integral of (6x^2+2x+3) ?
The integral of (6x^2+2x+3) is 2x^3+x^2+3x+C