What is the integral of (x^2+40x-16)/(x^3-16x) ?

The integral of (x^2+40x-16)/(x^3-16x) is ln|x|-5ln|x+4|+5ln|x-4|+C

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integral of (x^2+40x-16)/(x^3-16x)

\int \frac{x ^{2} + 40 x - 16}{x ^{3} - 16 x} d x

ln ∣ x ∣ - 5 ln ∣ x + 4 ∣ + 5 ln ∣ x - 4 ∣ + C

Solution steps

\int \frac{x ^{2} + 40 x - 16}{x ^{3} - 16 x} d x

Take the partial fraction of

\frac{x ^{2} + 40 x - 16}{x ^{3} - 16 x} : \frac{1}{x} - \frac{5}{x + 4} + \frac{5}{x - 4}

= \int \frac{1}{x} - \frac{5}{x + 4} + \frac{5}{x - 4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x - \int \frac{5}{x + 4} d x + \int \frac{5}{x - 4} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int \frac{5}{x + 4} d x = 5 ln ∣ x + 4 ∣

\int \frac{5}{x - 4} d x = 5 ln ∣ x - 4 ∣

= ln ∣ x ∣ - 5 ln ∣ x + 4 ∣ + 5 ln ∣ x - 4 ∣

Add a constant to the solution

= ln ∣ x ∣ - 5 ln ∣ x + 4 ∣ + 5 ln ∣ x - 4 ∣ + C

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What is the integral of (x^2+40x-16)/(x^3-16x) ?
The integral of (x^2+40x-16)/(x^3-16x) is ln|x|-5ln|x+4|+5ln|x-4|+C