What is the integral of sin(t)e^{cos(t)} ?

The integral of sin(t)e^{cos(t)} is -e^{cos(t)}+C

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integral of sin(t)e^{cos(t)}

\int sin (t) e^{c o s (t)} d t

- e^{c o s (t)} + C

Solution steps

\int sin (t) e^{c o s (t)} d t

Apply u-substitution

: \int - e^{u} d u

= \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - e^{u}

Substitute back

u = cos (t)

= - e^{c o s (t)}

Add a constant to the solution

= - e^{c o s (t)} + C

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What is the integral of sin(t)e^{cos(t)} ?
The integral of sin(t)e^{cos(t)} is -e^{cos(t)}+C