What is inverse oflaplace (12)/((3s-5)) ?

The answer to inverse oflaplace (12)/((3s-5)) is 4e^{(5t)/3}

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inverse oflaplace (12)/((3s-5))

inverse laplace

\frac{12}{( 3 s - 5 )}

4 e^{\frac{5 t}{3}}

Solution steps

L^{- 1} {\frac{12}{( 3 s - 5 )}}

= L^{- 1} {4 \cdot \frac{1}{s - \frac{5}{3}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {\frac{1}{s - \frac{5}{3}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - \frac{5}{3}}} = e^{\frac{5 t}{3}}

= 4 e^{\frac{5 t}{3}}

\int \frac{1}{n ^{3}}

(- 5, - 8), (5, 2)

x \to \infty lim (3 + \frac{4}{x})

\frac{d}{d x} (\frac{6 - x e ^{x}}{x + e ^{x}})

\int \frac{3 x ^{2}}{x ^{2} + 7} d x

What is inverse oflaplace (12)/((3s-5)) ?
The answer to inverse oflaplace (12)/((3s-5)) is 4e^{(5t)/3}