What is the integral of tan^2(3/4)x ?

The integral of tan^2(3/4)x is (tan^2(3/4)x^2)/2+C

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integral of tan^2(3/4)x

\int tan^{2} (\frac{3}{4}) x d x

\frac{tan ^{2} ( \frac{3}{4} ) x ^{2}}{2} + C

Solution steps

\int tan^{2} (\frac{3}{4}) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= tan^{2} (\frac{3}{4}) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= tan^{2} (\frac{3}{4}) \frac{x ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{tan ^{2} ( \frac{3}{4} ) x ^{2}}{2}

Add a constant to the solution

= \frac{tan ^{2} ( \frac{3}{4} ) x ^{2}}{2} + C

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What is the integral of tan^2(3/4)x ?
The integral of tan^2(3/4)x is (tan^2(3/4)x^2)/2+C