What is the derivative of h(x)=(sqrt(3))/(x^3+1) ?

The derivative of h(x)=(sqrt(3))/(x^3+1) is -(3sqrt(3)x^2)/((x^3+1)^2)

What is the first derivative of h(x)=(sqrt(3))/(x^3+1) ?

The first derivative of h(x)=(sqrt(3))/(x^3+1) is -(3sqrt(3)x^2)/((x^3+1)^2)

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derivative of

h (x) = \frac{3}{x ^{3} + 1}

- \frac{3 3 x ^{2}}{( x ^{3} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{3} + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x ^{3} + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x^{3} + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{3} + 1 ) ^{2}} \frac{d}{d x} (x^{3} + 1)

= - \frac{1}{( x ^{3} + 1 ) ^{2}} \frac{d}{d x} (x^{3} + 1)

\frac{d}{d x} (x^{3} + 1) = 3 x^{2}

= 3 (- \frac{1}{( x ^{3} + 1 ) ^{2}} \cdot 3 x^{2})

Simplify

3 (- \frac{1}{( x ^{3} + 1 ) ^{2}} \cdot 3 x^{2}) : - \frac{3 3 x ^{2}}{( x ^{3} + 1 ) ^{2}}

= - \frac{3 3 x ^{2}}{( x ^{3} + 1 ) ^{2}}

9 (t + 1) \frac{d y}{d t} - 5 y = 20 t

\frac{- 2 e ^{s}}{( s ^{2} - 2 s - 8 )}

x \to \infty lim ((x)^{x})

\int \frac{u}{1 - u} d u

\int x^{- 3} ln (5 x) d x

What is the derivative of h(x)=(sqrt(3))/(x^3+1) ?
The derivative of h(x)=(sqrt(3))/(x^3+1) is -(3sqrt(3)x^2)/((x^3+1)^2)
What is the first derivative of h(x)=(sqrt(3))/(x^3+1) ?
The first derivative of h(x)=(sqrt(3))/(x^3+1) is -(3sqrt(3)x^2)/((x^3+1)^2)