What is the integral of t^3sqrt(3t^4+3) ?

The integral of t^3sqrt(3t^4+3) is 1/18 (3t^4+3)^{3/2}+C

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integral of t^3sqrt(3t^4+3)

\int t^{3} 3 t^{4} + 3 d t

\frac{1}{18} (3 t^{4} + 3)^{\frac{3}{2}} + C

Solution steps

\int t^{3} 3 t^{4} + 3 d t

Apply u-substitution

: \int \frac{u}{12} d u

= \int \frac{u}{12} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{12} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{12} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 3 t^{4} + 3

= \frac{1}{12} \cdot \frac{2}{3} (3 t^{4} + 3)^{\frac{3}{2}}

Simplify

\frac{1}{12} \cdot \frac{2}{3} (3 t^{4} + 3)^{\frac{3}{2}} : \frac{1}{18} (3 t^{4} + 3)^{\frac{3}{2}}

= \frac{1}{18} (3 t^{4} + 3)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{18} (3 t^{4} + 3)^{\frac{3}{2}} + C

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What is the integral of t^3sqrt(3t^4+3) ?
The integral of t^3sqrt(3t^4+3) is 1/18 (3t^4+3)^{3/2}+C