What is the integral of 1-sec^2(x) ?

The integral of 1-sec^2(x) is x-tan(x)+C

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integral of 1-sec^2(x)

\int 1 - sec^{2} (x) d x

x - tan (x) + C

Solution steps

\int 1 - sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x - \int sec^{2} (x) d x

\int 1 d x = x

\int sec^{2} (x) d x = tan (x)

= x - tan (x)

Add a constant to the solution

= x - tan (x) + C

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