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Popular >

y^'=x^4-1/x y

Solution

y^{^{'}} = x^{4} - \frac{1}{x} y

Solution

y = \frac{x ^{5}}{6} + \frac{c _{1}}{x}

Solution steps

y^{'} (x) = x^{4} - \frac{1}{x} y

Solve linear ODE:

y = \frac{x ^{5}}{6} + \frac{c _{1}}{x}

y = \frac{x ^{5}}{6} + \frac{c _{1}}{x}

Popular Examples

integral from 0 to 1 of x^2ln(x)

\int_{0}^{1} x^{2} ln (x) d x

derivative of 1/((1-x^6^{3/2)})

\frac{d}{d x} (\frac{1}{( 1 - x ^{6} ) ^{\frac{3}{2}}})

integral from 0 to N of e^{-st}e^{-3t}

\int_{0}^{N} e^{- s t} e^{- 3 t} d t

y^'-(4x-y+1)^2=0

y^{^{'}} - (4 x - y + 1)^{2} = 0

derivative of 1/0

\frac{d}{d x} (\frac{1}{0})

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^4-1/x y ?
The solution for y^'=x^4-1/x y is y=(x^5)/6+(c_{1})/x