What is the integral of e^x+1/(x^2) ?

The integral of e^x+1/(x^2) is e^x-1/x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^x+1/(x^2)

\int e^{x} + \frac{1}{x ^{2}} d x

e^{x} - \frac{1}{x} + C

Solution steps

\int e^{x} + \frac{1}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} d x + \int \frac{1}{x ^{2}} d x

\int e^{x} d x = e^{x}

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

= e^{x} - \frac{1}{x}

Add a constant to the solution

= e^{x} - \frac{1}{x} + C

\int \frac{1}{( 5 - 4 x - x ^{2} ) ^{3}} d x

\int \frac{x}{x ^{2} + x - 12} d x

\int e^{1 - x} cos (2 x) d x

\int x^{3} ln (e^{x}) d x

\int \frac{3 y ^{4} + 12 y ^{2} - 1}{y ^{3} + 4 y} d y