What is the integral of 18x^2(sqrt(3x^2+5)) ?

The integral of 18x^2(sqrt(3x^2+5)) is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 18x^2(sqrt(3x^2+5))

\int 18 x^{2} (3 x^{2} + 5) d x

503 (- \frac{1}{4} (\frac{3}{2 5} x \frac{1}{5} (5 + 3 x^{2}) + \frac{1}{2} ln \frac{3}{5} x + \frac{1}{5} (5 + 3 x^{2})) + \frac{3}{100} x (3 x^{2} + 5)^{\frac{3}{2}}) + C

Solution steps

\int 18 x^{2} 3 x^{2} + 5 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 18 \cdot \int x^{2} 3 x^{2} + 5 d x

Apply Trigonometric Substitution

: \int \frac{25}{3 3} sec^{3} (u) tan^{2} (u) d u

= 18 \cdot \int \frac{25}{3 3} sec^{3} (u) tan^{2} (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 18 \cdot \frac{25}{3 3} \cdot \int sec^{3} (u) tan^{2} (u) d u

Rewrite using trig identities

= 18 \cdot \frac{25}{3 3} \cdot \int sec^{3} (u) (- 1 + sec^{2} (u)) d u

Expand

sec^{3} (u) (- 1 + sec^{2} (u)) : - sec^{3} (u) + sec^{5} (u)

= 18 \cdot \frac{25}{3 3} \cdot \int - sec^{3} (u) + sec^{5} (u) d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 18 \cdot \frac{25}{3 3} (- \int sec^{3} (u) d u + \int sec^{5} (u) d u)

\int sec^{3} (u) d u = \frac{1}{2} sec (u) tan (u) + \frac{1}{2} ln ∣ tan (u) + sec (u) ∣

\int sec^{5} (u) d u = \frac{sec ^{4} ( u ) sin ( u )}{4} + \frac{3}{4} (\frac{1}{2} sec (u) tan (u) + \frac{1}{2} ln ∣ tan (u) + sec (u) ∣)

= 18 \cdot \frac{25}{3 3} (- (\frac{1}{2} sec (u) tan (u) + \frac{1}{2} ln ∣ tan (u) + sec (u) ∣) + \frac{sec ^{4} ( u ) sin ( u )}{4} + \frac{3}{4} (\frac{1}{2} sec (u) tan (u) + \frac{1}{2} ln ∣ tan (u) + sec (u) ∣))

Substitute back

u = arctan (\frac{3}{5} x)

= 18 \cdot \frac{25}{3 3} - (\frac{1}{2} sec (arctan (\frac{3}{5} x)) tan (arctan (\frac{3}{5} x)) + \frac{1}{2} ln tan (arctan (\frac{3}{5} x)) + sec (arctan (\frac{3}{5} x))) + \frac{sec ^{4} ( arctan ( \frac{3}{5} x ) ) sin ( arctan ( \frac{3}{5} x ) )}{4} + \frac{3}{4} (\frac{1}{2} sec (arctan (\frac{3}{5} x)) tan (arctan (\frac{3}{5} x)) + \frac{1}{2} ln tan (arctan (\frac{3}{5} x)) + sec (arctan (\frac{3}{5} x)))

Simplify

18 \cdot \frac{25}{3 3} - (\frac{1}{2} sec (arctan (\frac{3}{5} x)) tan (arctan (\frac{3}{5} x)) + \frac{1}{2} ln tan (arctan (\frac{3}{5} x)) + sec (arctan (\frac{3}{5} x))) + \frac{sec ^{4} ( arctan ( \frac{3}{5} x ) ) sin ( arctan ( \frac{3}{5} x ) )}{4} + \frac{3}{4} (\frac{1}{2} sec (arctan (\frac{3}{5} x)) tan (arctan (\frac{3}{5} x)) + \frac{1}{2} ln tan (arctan (\frac{3}{5} x)) + sec (arctan (\frac{3}{5} x))) : 503 (- \frac{1}{4} (\frac{3}{2 5} x \frac{1}{5} (5 + 3 x^{2}) + \frac{1}{2} ln \frac{3}{5} x + \frac{1}{5} (5 + 3 x^{2})) + \frac{3}{100} x (3 x^{2} + 5)^{\frac{3}{2}})

= 503 (- \frac{1}{4} (\frac{3}{2 5} x \frac{1}{5} (5 + 3 x^{2}) + \frac{1}{2} ln \frac{3}{5} x + \frac{1}{5} (5 + 3 x^{2})) + \frac{3}{100} x (3 x^{2} + 5)^{\frac{3}{2}})

Add a constant to the solution

= 503 (- \frac{1}{4} (\frac{3}{2 5} x \frac{1}{5} (5 + 3 x^{2}) + \frac{1}{2} ln \frac{3}{5} x + \frac{1}{5} (5 + 3 x^{2})) + \frac{3}{100} x (3 x^{2} + 5)^{\frac{3}{2}}) + C

\int x \cdot x^{2} - 2 d x

\int \frac{x ^{4}}{( x + 1 ) ( x + 2 ) ( x + 3 )} d x

\int \frac{1}{15 - x ^{2}} d x

\int 6 sin (2 x + 1) d x

\int \frac{21}{x 1 + 2 x} d x

What is the integral of 18x^2(sqrt(3x^2+5)) ?
The integral of 18x^2(sqrt(3x^2+5)) is