What is the integral of (ln|4x^2|)/x ?

The integral of (ln|4x^2|)/x is ln^2(2x)+C

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integral of (ln|4x^2|)/x

\int \frac{ln 4 x ^{2}}{x} d x

ln^{2} (2 x) + C

Solution steps

\int \frac{ln 4 x ^{2}}{x} d x

Simplify

\frac{ln 4 x ^{2}}{x} : \frac{2 ln ( 2 x )}{x}

= \int \frac{2 ln ( 2 x )}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{ln ( 2 x )}{x} d x

Apply u-substitution

: \int \frac{ln ( u )}{u} d u

= 2 \cdot \int \frac{ln ( u )}{u} d u

Apply u-substitution

: \int v d v

= 2 \cdot \int v d v

Apply the Power Rule

: \frac{v ^{2}}{2}

= 2 \cdot \frac{v ^{2}}{2}

Substitute back

= 2 \cdot \frac{ln ^{2} ( 2 x )}{2}

Simplify

2 \cdot \frac{ln ^{2} ( 2 x )}{2} : ln^{2} (2 x)

= ln^{2} (2 x)

Add a constant to the solution

= ln^{2} (2 x) + C

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What is the integral of (ln|4x^2|)/x ?
The integral of (ln|4x^2|)/x is ln^2(2x)+C