What is the integral of (e^x-sec^2(x)) ?

The integral of (e^x-sec^2(x)) is e^x-tan(x)+C

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integral of (e^x-sec^2(x))

\int (e^{x} - sec^{2} (x)) d x

e^{x} - tan (x) + C

Solution steps

\int e^{x} - sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} d x - \int sec^{2} (x) d x

\int e^{x} d x = e^{x}

\int sec^{2} (x) d x = tan (x)

= e^{x} - tan (x)

Add a constant to the solution

= e^{x} - tan (x) + C

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What is the integral of (e^x-sec^2(x)) ?
The integral of (e^x-sec^2(x)) is e^x-tan(x)+C