What is (\partial)/(\partial h)(pir^2h) ?

The answer to (\partial)/(\partial h)(pir^2h) is pir^2

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(\partial)/(\partial h)(pir^2h)

\frac{\partial}{\partial h} (π r^{2} h)

π r^{2}

Solution steps

\frac{\partial}{\partial h} (π r^{2} h)

Treat

r

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= π r^{2} \frac{\partial}{\partial h} (h)

Apply the common derivative:

\frac{\partial}{\partial h} (h) = 1

= π r^{2} \cdot 1

Simplify

= π r^{2}

\frac{\partial}{\partial x} (sin (x) sin (y))

(x \cdot \frac{d y}{d x} - y) cos (\frac{y}{x}) + x = 0

\int \frac{x ^{6} + 2 x ^{4} + 6 x - 9}{x ^{3} + 3} d x

\frac{6}{( 1 - x ) ^{3}}

k \to \infty lim ((- 1)^{k})

What is (\partial)/(\partial h)(pir^2h) ?
The answer to (\partial)/(\partial h)(pir^2h) is pir^2