What is the integral of-(2cos(s))/(sin^2(s)) ?

The integral of-(2cos(s))/(sin^2(s)) is 2csc(s)+C

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integral of-(2cos(s))/(sin^2(s))

\int - \frac{2 cos ( s )}{sin ^{2} ( s )} d s

2 csc (s) + C

Solution steps

\int - \frac{2 cos ( s )}{sin ^{2} ( s )} d s

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{cos ( s )}{sin ^{2} ( s )} d s

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= - 2 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - 2 (- \frac{1}{u})

Substitute back

u = sin (s)

= - 2 (- \frac{1}{sin ( s )})

Simplify

- 2 (- \frac{1}{sin ( s )}) : 2 csc (s)

= 2 csc (s)

Add a constant to the solution

= 2 csc (s) + C

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What is the integral of-(2cos(s))/(sin^2(s)) ?
The integral of-(2cos(s))/(sin^2(s)) is 2csc(s)+C