What is the integral of \sqrt[7]{x^9} ?

The integral of \sqrt[7]{x^9} is 7/16 x^{16/7}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of \sqrt[7]{x^9}

\frac{7}{16} x^{\frac{16}{7}} + C

Solution steps

assuming

x \geq 0

= \int x^{\frac{9}{7}} d x

Apply the Power Rule

: \frac{7}{16} x^{\frac{16}{7}}

= \frac{7}{16} x^{\frac{16}{7}}

Add a constant to the solution

= \frac{7}{16} x^{\frac{16}{7}} + C

\int \frac{1}{36 - 25 x ^{2}} d x

\int 3 sec^{4} (3 x) d x

\int \frac{3 z}{x ^{2} + z ^{2}} d x

\int e^{x} sin (y) - 2 y sin (x) d x

\int \frac{e ^{2 x}}{e ^{2 x} + 1} d x

What is the integral of \sqrt[7]{x^9} ?
The integral of \sqrt[7]{x^9} is 7/16 x^{16/7}+C