What is the integral of 5x^4-5/(x^2) ?

The integral of 5x^4-5/(x^2) is x^5+5/x+C

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integral of 5x^4-5/(x^2)

\int 5 x^{4} - \frac{5}{x ^{2}} d x

x^{5} + \frac{5}{x} + C

Solution steps

\int 5 x^{4} - \frac{5}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{4} d x - \int \frac{5}{x ^{2}} d x

\int 5 x^{4} d x = x^{5}

\int \frac{5}{x ^{2}} d x = - \frac{5}{x}

= x^{5} - (- \frac{5}{x})

Simplify

= x^{5} + \frac{5}{x}

Add a constant to the solution

= x^{5} + \frac{5}{x} + C

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What is the integral of 5x^4-5/(x^2) ?
The integral of 5x^4-5/(x^2) is x^5+5/x+C