What is laplacetransform (2(t-2)^2)+10(t-2)+15 ?

The answer to laplacetransform (2(t-2)^2)+10(t-2)+15 is 4/(s^3)+2/(s^2)+3/s

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laplacetransform (2(t-2)^2)+10(t-2)+15

laplace transform

(2 (t - 2)^{2}) + 10 (t - 2) + 15

\frac{4}{s ^{3}} + \frac{2}{s ^{2}} + \frac{3}{s}

Solution steps

L {(2 (t - 2)^{2}) + 10 (t - 2) + 15}

Expand

2 (t - 2)^{2} + 10 (t - 2) + 15 : 2 t^{2} + 2 t + 3

= L {2 t^{2} + 2 t + 3}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 2 L {t^{2}} + 2 L {t} + L {3}

L {t^{2}} : \frac{2}{s ^{3}}

L {t} : \frac{1}{s ^{2}}

L {3} : \frac{3}{s}

= 2 \cdot \frac{2}{s ^{3}} + 2 \cdot \frac{1}{s ^{2}} + \frac{3}{s}

Refine

2 \frac{2}{s ^{3}} + 2 \frac{1}{s ^{2}} + \frac{3}{s} : \frac{4}{s ^{3}} + \frac{2}{s ^{2}} + \frac{3}{s}

= \frac{4}{s ^{3}} + \frac{2}{s ^{2}} + \frac{3}{s}

\int \frac{1}{x ( ln ( x ) ) ^{8}} d x

\int \frac{2 + x + x}{x} d x

(sec (x))^{^{'}}

0.334 \cdot sin (0.3494 x - 0.06988)

\frac{d}{d x} (6 + sec (π) x^{2})

What is laplacetransform (2(t-2)^2)+10(t-2)+15 ?
The answer to laplacetransform (2(t-2)^2)+10(t-2)+15 is 4/(s^3)+2/(s^2)+3/s