What is the integral of (x^2-1)/(2x) ?

The integral of (x^2-1)/(2x) is 1/2 ((x^2)/2-ln|x|)+C

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integral of (x^2-1)/(2x)

\int \frac{x ^{2} - 1}{2 x} d x

\frac{1}{2} (\frac{x ^{2}}{2} - ln ∣ x ∣) + C

Solution steps

\int \frac{x ^{2} - 1}{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{x ^{2} - 1}{x} d x

Expand

\frac{x ^{2} - 1}{x} : x - \frac{1}{x}

= \frac{1}{2} \cdot \int x - \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int x d x - \int \frac{1}{x} d x)

\int x d x = \frac{x ^{2}}{2}

\int \frac{1}{x} d x = ln ∣ x ∣

= \frac{1}{2} (\frac{x ^{2}}{2} - ln ∣ x ∣)

Add a constant to the solution

= \frac{1}{2} (\frac{x ^{2}}{2} - ln ∣ x ∣) + C

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What is the integral of (x^2-1)/(2x) ?
The integral of (x^2-1)/(2x) is 1/2 ((x^2)/2-ln|x|)+C