What is the integral of \sqrt[3]{4x^2} ?

The integral of \sqrt[3]{4x^2} is \sqrt[3]{4}x^{5/3}-(2*2^{2/3})/5 x^{5/3}+C

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integral of \sqrt[3]{4x^2}

Solution steps

Apply Integration By Parts

\int \frac{8 x ^{2}}{3 \cdot 4 ^{\frac{2}{3}} ( x ^{2} ) ^{\frac{2}{3}}} d x = \frac{2 ^{1 + \frac{2}{3}}}{5} x^{\frac{5}{3}}

Simplify

Add a constant to the solution

\int \frac{8 e ^{2 x}}{3 + e ^{x}} d x

\int \frac{3 - 3 x ^{2} + 2}{3 x ^{2} + 2} d x

\int 3 x + x^{2} d x

\int x^{3} sin (x^{2} + 1) d x

\int \frac{5 x ^{3} - 8}{x ^{3}} d x

What is the integral of \sqrt[3]{4x^2} ?
The integral of \sqrt[3]{4x^2} is \sqrt[3]{4}x^{5/3}-(2*2^{2/3})/5 x^{5/3}+C