What is the integral of x*3^{x^2} ?

The integral of x*3^{x^2} is 1/(2ln(3))*3^{x^2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x*3^{x^2}

\int x \cdot 3^{x^{2}} d x

\frac{1}{2 ln ( 3 )} \cdot 3^{x^{2}} + C

Solution steps

\int x \cdot 3^{x^{2}} d x

Apply u-substitution

: \int \frac{1}{2 ln ( 3 )} d u

= \int \frac{1}{2 ln ( 3 )} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{2 ln ( 3 )} u

Substitute back

u = 3^{x^{2}}

= \frac{1}{2 ln ( 3 )} \cdot 3^{x^{2}}

Add a constant to the solution

= \frac{1}{2 ln ( 3 )} \cdot 3^{x^{2}} + C

\int (1 - y)^{4} d y

\int \frac{d}{d x} (\frac{1}{x ^{2} + 1}) d x

\int 13 sin^{3} (x) cos^{2} (x) d x

\int \frac{4 x - 2}{( x ) ( x + 1 ) ( x - 2 )} d x

What is the integral of x*3^{x^2} ?
The integral of x*3^{x^2} is 1/(2ln(3))*3^{x^2}+C