What is the integral of (5x)/((x-2)(x-3)) ?

The integral of (5x)/((x-2)(x-3)) is 5(-2ln|x-2|+3ln|x-3|)+C

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integral of (5x)/((x-2)(x-3))

\int \frac{5 x}{( x - 2 ) ( x - 3 )} d x

5 (- 2 ln ∣ x - 2 ∣ + 3 ln ∣ x - 3 ∣) + C

Solution steps

\int \frac{5 x}{( x - 2 ) ( x - 3 )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{x}{( x - 2 ) ( x - 3 )} d x

Apply u-substitution

: \int \frac{u + 2}{u ( u - 1 )} d u

= 5 \cdot \int \frac{u + 2}{u ( u - 1 )} d u

Take the partial fraction of

\frac{u + 2}{u ( u - 1 )} : - \frac{2}{u} + \frac{3}{u - 1}

= 5 \cdot \int - \frac{2}{u} + \frac{3}{u - 1} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 5 (- \int \frac{2}{u} d u + \int \frac{3}{u - 1} d u)

\int \frac{2}{u} d u = 2 ln ∣ u ∣

\int \frac{3}{u - 1} d u = 3 ln ∣ u - 1 ∣

= 5 (- 2 ln ∣ u ∣ + 3 ln ∣ u - 1 ∣)

Substitute back

u = x - 2

= 5 (- 2 ln ∣ x - 2 ∣ + 3 ln ∣ x - 2 - 1 ∣)

Simplify

= 5 (- 2 ln ∣ x - 2 ∣ + 3 ln ∣ x - 3 ∣)

Add a constant to the solution

= 5 (- 2 ln ∣ x - 2 ∣ + 3 ln ∣ x - 3 ∣) + C

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What is the integral of (5x)/((x-2)(x-3)) ?
The integral of (5x)/((x-2)(x-3)) is 5(-2ln|x-2|+3ln|x-3|)+C